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Exercise 4.3 · Q26

Q.Examine the consistency of the following equations: 2x−y+3=0, 3x+y−2=0, 11x+2y−3=02x-y+3=0,\ 3x+y-2=0,\ 11x+2y-3=0

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By the consistency condition, D=∣2−1331−2112−3∣=2(−3+4)+1(−9+22)+3(6−11)=2(1)+1(13)+3(−5)=2+13−15=0D=\begin{vmatrix}2&-1&3\\3&1&-2\\11&2&-3\end{vmatrix}=2(-3+4)+1(-9+22)+3(6-11)=2(1)+1(13)+3(-5)=2+13-15=0.

Since D=0D=0, check that the equations actually share a common solution. From 2x−y+3=02x-y+3=0: y=2x+3y=2x+3. Substitute in 3x+y−2=03x+y-2=0: 3x+2x+3−2=0⇒5x+1=0⇒x=−153x+2x+3-2=0\Rightarrow 5x+1=0\Rightarrow x=-\dfrac15, so y=2(−15)+3=135y=2\left(-\dfrac15\right)+3=\dfrac{13}{5}. …

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