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Miscellaneous Exercise 4(A) · Q42

Q.The value of a for which the system of equations a3x+(a+1)3y+(a+2)3z=0a^3x+(a+1)^3y+(a+2)^3z=0, ax+(a+1)y+(a+2)z=0ax+(a+1)y+(a+2)z=0 and x+y+z=0x+y+z=0 has a non-zero solution is
A) 0
B) -1
C) 1
D) 2

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For the homogeneous system to have a non-zero solution, D=∣a3(a+1)3(a+2)3aa+1a+2111∣=0D=\begin{vmatrix}a^3&(a+1)^3&(a+2)^3\\a&a+1&a+2\\1&1&1\end{vmatrix}=0. Testing a=−1a=-1: row 1 becomes (−1,0,1)(-1,0,1) and row 2 becomes (−1,0,1)(-1,0,1) — identical rows, so D=0D=0 immediately. Testing the other options …

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