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Exercise 4.3 · Q28

Q.Examine the consistency of the following equations: x+2y−3=0, 7x+4y−11=0, 2x+4y−6=0x+2y-3=0,\ 7x+4y-11=0,\ 2x+4y-6=0

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Coefficient rows are (1,2,−3)(1,2,-3), (7,4,−11)(7,4,-11), (2,4,−6)(2,4,-6). Since (2,4,−6)=2×(1,2,−3)(2,4,-6)=2\times(1,2,-3), row 3 is proportional to row 1, so D=∣12−374−1124−6∣=0D=\begin{vmatrix}1&2&-3\\7&4&-11\\2&4&-6\end{vmatrix}=0.

Solve the first two equations: x+2y=3x+2y=3 and 7x+4y=117x+4y=11. From the first, x=3−2yx=3-2y. Substitute: 7(3−2y)+4y=11⇒21−14y+4y=11⇒−10y=−10⇒y=17(3-2y)+4y=11\Rightarrow21-14y+4y=11\Rightarrow-10y=-10\Rightarrow y=1, so x=1x=1. …

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