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Numerical · Q37

Q.In a EM wave the electric field oscillates sinusoidally at a frequency of 2×\times1010^{10} Hz. What is the wavelength of the wave?

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Applying λ=cν=3×108 m/s2×1010 Hz=1.5×10−2\lambda=\dfrac{c}{\nu}=\dfrac{3\times10^{8}\ \text{m/s}}{2\times10^{10}\ \text{Hz}}=1.5\times10^{-2} m. This is exactly the microwave/high-frequency-radio wavelength scale, and the underlying frequency-oscillation relation is precisely the sinusoidal Ey=E0sin⁡(kx−ωt)E_y=E_0\sin(kx-\omega t) form described in s …

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