Q.At which place on the Earth's surface is the gravitational acceleration maximum? Why?
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Start your 14-day free trial to unlock the full solution →Two effects reduce the acceleration due to gravity away from its 'ideal' (non-rotating, perfectly spherical) value: the Earth's rotation, which requires part of the gravitational pull to supply the centripetal force keeping a surface point moving in its daily circle (, maximum reduction at the equator, zero reduction at the poles since points on the axis of rotation do not move in a circle at all), and the Earth's oblate (equator-bulging) shape, which gives the equator a LARGER radius than the poles, further weakening g there since . Both effects vanish, or are minimised, at the poles: there is no rotational reduction (poles lie exactly on the rotation axis) and the polar radius is the smallest of any latitude, giving the largest possible value of $GM/ …
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