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Answer in Detail · Q27

Q.At which place on the Earth's surface is the gravitational acceleration maximum? Why?

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
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Two effects reduce the acceleration due to gravity away from its 'ideal' (non-rotating, perfectly spherical) value: the Earth's rotation, which requires part of the gravitational pull to supply the centripetal force keeping a surface point moving in its daily circle (g′=g−Rω2cos⁡2θg'=g-R\omega^2\cos^2\theta, maximum reduction at the equator, zero reduction at the poles since points on the axis of rotation do not move in a circle at all), and the Earth's oblate (equator-bulging) shape, which gives the equator a LARGER radius than the poles, further weakening g there since g∝1/r2g\propto1/r^2. Both effects vanish, or are minimised, at the poles: there is no rotational reduction (poles lie exactly on the rotation axis) and the polar radius is the smallest of any latitude, giving the largest possible value of $GM/ …

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