Q.40000 litre of oil of density 0.9 g/cc is pumped from an oil tanker ship into a storage tank at 10 m higher level than the ship, in half an hour. What should be the power of the pump?

[!TLDR] Using mass = density x volume, and Power = mgh/time, the pump's power …

Volume of oil = 40000 litre = 40 m^3 (since 1000 litre = 1 m^3). Density = 0.9 g/cc = 900 kg/m^3. Mass $m=\text{density}\times\text{volume}=900\times 40=36000$ kg. Height raised, $h=10$ m; $g=10$ m/s^2 (given, or standard). Work done against gravity $=mgh=36000\times10\times10=3.6\times10^6$ J. Time taken $=$ half an hour $=1800$ s. Power $=\frac{\text{Work}}{\text{time}}=\frac{3.6\time …

Convert the given volume and density to mass, compute the work done raising that mass through the given height (W …

Forgetting to convert litres to cubic metres (or g/cc to kg/m^3) consistently before multiplying, l …