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Answer Questions · Q6

Q.Show that a⃗=i^−j^2\vec{a} = \dfrac{\hat{i}-\hat{j}}{\sqrt{2}} is a unit vector.

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Step 1. a⃗=i^−j^2\vec a = \dfrac{\hat i - \hat j}{\sqrt2}, so its components are ax=12a_x = \dfrac{1}{\sqrt2} and ay=−12a_y = -\dfrac{1}{\sqrt2}.

Step 2. Magnitude: ∣a⃗∣=ax2+ay2=(12)2+(−12)2=12+12=1=1|\vec a| = \sqrt{a_x^2+a_y^2} = \sqrt{\left(\dfrac{1}{\sqrt2}\right)^2+\left(-\dfrac{1}{\sqrt2}\right)^2} = \sqrt{\dfrac12+\dfrac12} = \sqrt1 = 1.

Step 3. Since ∣a⃗∣=1|\vec a| = 1, by definition a⃗\vec a is a unit vector.

[!ANSWER] ∣a⃗∣=1|\vec a| = 1 — a⃗\vec a is indeed a unit vector.

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