Physical quantities fall into two fundamental classes. A scalar quantity is completely specified by a magnitude alone — a number together with a unit — with no reference to direction; mass, time, temperature, density, and distance travelled are all scalars, and they combine using the ordinary rules of algebra. A vector quantity needs both a magnitude AND a direction for its complete description; displacement, velocity, force, and momentum are common examples.
A vector is represented geometrically by a directed line segment (an arrow) drawn to scale, with its length giving the magnitude and its orientation giving the direction; the starting point is called the tail and the arrowhead end is called the head. Several named types of vectors recur throughout physics: the zero (null) vector, which has zero magnitude and an arbitrary direction (e.g. the velocity of a stationary body); the resultant vector, the single vector equivalent to two or more vectors acting together; the negative vector, which has the same magnitude as a given vector but points in exactly the opposite direction; equal vectors, which must share both the same magnitude and the same direction; the position vector, which locates a particle relative to a chosen origin; and the unit vector, a vector of magnitude exactly 1 obtained by dividing any non-zero vector by its own magnitude, u^M=M/∣M∣.
In a rectangular coordinate system, the unit vectors along the x, y, and z axes are denoted i^, j^, and k^ respectively, and every vector can be expressed in terms of these — the foundation for resolving vectors into components and for the algebraic (component) forms of vector addition and multiplication.
[!TLDR] A vector is a unit vector if its magnitude equals 1; computing ∣a∣ confirms this. [!ANSWER] ∣a∣=1, so a is a unit vector.
Step 1.a=2i^−j^, so its components are ax=21 and ay=−21.
Step 3. Since ∣a∣=1, by definition a is a unit vector.
[!ANSWER] ∣a∣=1 — a is indeed a unit vector.
Compute the magnitude ax2+ay2 and check whether it equals 1.
Forgetting to square the 1/2 terms correctly, or mishandling the negative sign on ay before squaring (which does not affect the result but is a common slip).