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Answer Questions · Q9

Q.Find a vector which is parallel to v⃗=i^−2j^\vec{v} = \hat{i}-2\hat{j} and has a magnitude 10.

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Step 1. v⃗=i^−2j^\vec v = \hat i-2\hat j, so ∣v⃗∣=12+(−2)2=5|\vec v| = \sqrt{1^2+(-2)^2} = \sqrt5.

Step 2. Unit vector along v⃗\vec v: v^=v⃗∣v⃗∣=i^−2j^5\hat v = \dfrac{\vec v}{|\vec v|} = \dfrac{\hat i-2\hat j}{\sqrt5}. …

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