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Solve Problems · Q16

Q.Using the rule for differentiation for quotient of two functions, prove that ddx(sin⁡xcos⁡x)=sec⁡2x\dfrac{d}{dx}\left(\dfrac{\sin x}{\cos x}\right) = \sec^2 x

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Step 1. Let f1(x)=sin⁡xf_1(x)=\sin x and f2(x)=cos⁡xf_2(x)=\cos x, so tan⁡x=f1f2\tan x = \dfrac{f_1}{f_2}.

Step 2. By the quotient rule, ddx(f1f2)=f2df1dx−f1df2dxf22=cos⁡x⋅cos⁡x−sin⁡x⋅(−sin⁡x)cos⁡2x\dfrac{d}{dx}\left(\dfrac{f_1}{f_2}\right) = \dfrac{f_2\frac{df_1}{dx}-f_1\frac{df_2}{dx}}{f_2^2} = \dfrac{\cos x\cdot\cos x - \sin x\cdot(-\sin x)}{\cos^2 x}.

Step 3. =cos⁡2x+sin⁡2xcos⁡2x= \dfrac{\cos^2 x+\sin^2 x}{\cos^2 x}. …

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