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Numericals · Q32

Q.At what temperature will the speed of sound in air be 1.75 times its speed at N.T.P?

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The speed of sound in air varies with absolute temperature as vv0=TT0\dfrac{v}{v_0}=\sqrt{\dfrac{T}{T_0}} (section 8.5.5(b)), with T0=273T_0=273 K (NTP). Given v=1.75 v0v=1.75\,v_0: 1.75=T2731.75=\sqrt{\dfrac{T}{273}}. Squaring both sides: T273=1.752=3.0625\dfrac{T}{273}=1.75^2=3.0625. So T=3.0625×273=836.06T=3.0625\times273=836.06 K. …

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