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Numericals · Q36

Q.The sound emitted from the siren of an ambulance has frequency of 1500 Hz. The speed of sound is 340 m/s. Calculate the difference in frequencies heard by a stationary observer if the ambulance initially travels towards and then away from the observer at a speed of 30 m/s.

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Given: emitted frequency n0=1500n_0=1500 Hz, speed of sound v=340v=340 m/s, source (ambulance) speed vs=30v_s=30 m/s, listener stationary. Approaching: n1=n0vv−vs=1500×340340−30=1500×340310=1500×1.09677≈1645.16n_1=n_0\dfrac{v}{v-v_s}=1500\times\dfrac{340}{340-30}=1500\times\dfrac{340}{310}=1500\times1.09677\approx1645.16 Hz. Receding: n2=n0vv+vs=1500×340340+30=1500×340370=1500×0.91892≈1378.38n_2=n_0\dfrac{v}{v+v_s}=1500\times\dfrac{340}{340+30}=1500\times\dfrac{340}{370}=1500\times0.91892\approx1378.38 Hz. **Difference …

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