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Worked Examples · Example 6

Q.Find the area of the region enclosed between the line y=xy=x and the parabola y=x2y=x^{2}.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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Step 1 — find the points of intersection. Set the two equations equal:

x=x2 ⇒ x2−x=0 ⇒ x(x−1)=0 ⇒ x=0 or x=1x=x^{2}\ \Rightarrow\ x^{2}-x=0\ \Rightarrow\ x(x-1)=0\ \Rightarrow\ x=0\ \text{or}\ x=1

So the limits of integration are a=0a=0 and b=1b=1.

Step 2 — decide which curve is on top. Test x=12x=\tfrac{1}{2}: the line gives y=12=0.5y=\tfrac{1}{2}=0.5, the parabola gives y=(12)2=0.25y=\left(\tfrac{1}{2}\right)^{2}=0.25. The line y=xy=x is above the parabola y=x2y=x^{2} on (0,1)(0,1), so upper =x=x, lower =x2=x^{2}.

Step 3 — integrate the difference (upper −- lower). …

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