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Q.Find the area enclosed between the circle x2+y2=1x^2+y^2=1 and the line x+y=1x+y=1 lying in the first quadrant.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2026Subjective· 4mImportance★★★★★
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The circle and line meet at (1,0)(1,0) and (0,1)(0,1); the enclosed area = quarter-circle area minus the triangle area.

The circle x2+y2=1x^2+y^2=1 and the line x+y=1x+y=1 both pass through (1,0)(1,0) and (0,1)(0,1) — the two points where the line is a chord of the circle in the first quadrant.

The region enclosed between the circle and the line in the first quadrant (the circular segment between the arc and the chord) can be found as:

Area=∫01ycircle dx−∫01yline dx=∫011−x2 dx−∫01(1−x) dx\text{Area}=\int_0^1 y_{\text{circle}}\,dx-\int_0^1 y_{\text{line}}\,dx=\int_0^1\sqrt{1-x^2}\,dx-\int_0^1(1-x)\,dx

First integral (quarter circle area): …

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