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Q.For the reaction, 3I−(aq)+S2O82−(aq)⟶I3−(aq)+2 SO42−(aq)\mathrm{3I^-(aq) + S_2O_8^{2-}(aq) \longrightarrow I_3^-(aq) + 2\ SO_4^{2-}(aq)}. Calculate the rate of formation of I3−_3^-, the rates of consumption of I−^- and S2_2O82−_8^{2-} and the overall rate of reaction if the rate of formation of SO42−_4^{2-} is 0.022 moles dm−3^{-3} sec−1^{-1}

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Step 1. For 3I-(aq) + S2O8^2-(aq) -> I3-(aq) + 2SO4^2-(aq), the general rate expression is rate = -(1/3)d[I-]/dt = -(1/1)d[S2O8^2-]/dt = (1/1)d[I3-]/dt = (1/2)d[SO4^2-]/dt.

Step 2. Given d[SO4^2-]/dt = 0.022 mol dm-3 s-1, the overall rate of reaction = (1/2)(0.022) = 0.011 mol dm-3 s-1.

Step 3. Rate of formation of I3- = rate of reaction (coefficient 1) = 0.011 mol dm-3 s-1.

Step 4. Rate of consumption of S2O8^2- = rate of reaction (coefficient 1) = 0.011 mol dm-3 s-1. …

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