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Q.Under what conditions ΔH=ΔU\Delta H = \Delta U?

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★
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ΔH\Delta H and ΔU\Delta U differ by PΔVP\Delta V (= ΔngRT\Delta n_g RT for gases); they are equal whenever that term vanishes.

Step 1. At constant pressure, ΔH=ΔU+PΔV\Delta H = \Delta U + P\Delta V.

Step 2. If the reaction involves only solids and liquids, the volume change is negligible (ΔV≈0\Delta V \approx 0), so ΔH≈ΔU\Delta H \approx \Delta U.

Step 3. For gas-phase reactions, ΔH=ΔU+ΔngRT\Delta H = \Delta U + \Delta n_g RT; the two are equal when Δng=0\Delta n_g = 0, i.e. moles of gaseous products = moles of gaseous reactants (e.g. H2(g)+I2(g)→2 HI(g)\mathrm{H_2(g) + I_2(g) \rightarrow 2\,HI(g)}). …

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