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Question 110 of 115

Q.ΔH\Delta H for formation of ethane gas is –84.4 kJ at 300 K. Calculate ΔU\Delta U for the reaction.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2025Subjective· 3mImportance★★★★★
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Δng=1−3=−2\Delta n_g=1-3=-2; ΔU=ΔH−ΔngRT=−84.4−(−2)(8.314×10−3)(300)≈−79.4\Delta U=\Delta H-\Delta n_gRT=-84.4-(-2)(8.314\times10^{-3})(300)\approx-79.4 kJ.

Formation of ethane: 2C(s)+3H2(g)→C2H6(g)2C(s) + 3H_2(g) \rightarrow C_2H_6(g)

Δng=(moles gaseous products)−(moles gaseous reactants)=1−3=−2\Delta n_g = (\text{moles gaseous products}) - (\text{moles gaseous reactants}) = 1 - 3 = -2

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