Answer the following (group 2) · Q14
Q.xiv. What is the oxidation state of xenon in the following compounds. XeOF, XeO, XeF, XeF, XeF.
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Start your 14-day free trial to unlock the full solution →Step 1. XeOF4: one O (-2) and four F (-1 each = -4); Xe + (-2) + (-4) = 0, so Xe = +6.
Step 2. XeO3: three O (-2 each = -6); Xe + (-6) = 0, so Xe = +6.
Step 3. XeF6: six F (-1 each = -6); Xe + (-6) = 0, so Xe = +6.
Step 4. XeF4: four F (-1 each = -4); Xe + (-4) = 0, so Xe = +4. …
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