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Select appropriate answers · Q9

Q.ix. BrCl reacts with water to form A. HBr
B. Br2_2 + Cl2_2
C. HOBr
D. HOBr + HCl

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Step 1. Section 7.12.2's "Hydrolysis gives oxoacids" row prints the reaction directly: BrCl + H2_2O ⟶\longrightarrow HOBr + HCl.

Step 2. The pattern: in an XX' interhalogen the larger, more electropositive halogen (Br) takes the -OH to give the hypohalous acid HOBr, while the smaller, more electronegative halogen (Cl) leaves as the hydrogen halide HCl. …

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