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Select appropriate answers · Q10

Q.x. Chlorine reacts with excess of fluorine to form. A. ClF
B. ClF3_3
C. ClF2_2
D. Cl2_2F3_3

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Step 1. Section 7.12.2's preparation methods state: Cl2 + 3F2 (with F2 in excess) gives 2ClF3.

Step 2. With only equal (not excess) volumes of Cl2 and F2, the product is instead the simpler ClF (Cl2 + F2 -> 2ClF). …

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