Skip to content

Chemistry · Ch 3 — Ionic Equilibria

Salts of strong acids and weak bases

3.7.4

Salts of strong acids and weak bases

CuSO4\mathrm{CuSO_4} is salt of strong acid H2SO4\mathrm{H_2SO_4} and weak base Cu(OH)2\mathrm{Cu(OH)_2}. When CuSO4\mathrm{CuSO_4} is dissolved in water, it dissociates completely as,

CuSO4(aq)→Cu2+(aq)+SO42−(aq)\mathrm{CuSO_4(aq)} \rightarrow \mathrm{Cu^{2+}(aq)} + \mathrm{SO_4^{2-}(aq)}

SO42−\mathrm{SO_4^{2-}} ions of salt have no tendency to react with water because the possible product H2SO4\mathrm{H_2SO_4} is strong electrolyte. The reaction of Cu2+\mathrm{Cu^{2+}} ions with OH−\mathrm{OH^{-}} ions forms unionized Cu(OH)2\mathrm{Cu(OH)_2}. The hydrolytic equilibrium for CuSO4\mathrm{CuSO_4} is then written as,

Cu2+(aq)+4H2O(l)⇌Cu(OH)2(aq)+2H3O+(aq)\mathrm{Cu^{2+}(aq)} + 4\mathrm{H_2O}(l) \rightleftharpoons \mathrm{Cu(OH)_2(aq)} + 2\mathrm{H_3O^{+}(aq)}

Due to the presence of excess of H3O+\mathrm{H_3O^{+}} ions, the resulting solution of CuSO4\mathrm{CuSO_4} becomes acidic and turns blue litmus red. …