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Exercise 5.1 · Q11

Q.Find the area of the region included between: y2=4xy^2 = 4x, line y=xy = x

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Substituting y=xy=x into y2=4xy^2=4x: x2=4x⇒x(x−4)=0⇒x=0,4x^2 = 4x \Rightarrow x(x-4)=0 \Rightarrow x=0,4. Between x=0x=0 and x=4x=4, the parabola's upper branch y=2xy=2\sqrt x lies above the line y=xy=x. So …

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