Skip to content
Question 132 of 160

Q.The displacement 's' of a moving particle at time 't' is given by s=5+20t−2t2s = 5 + 20t - 2t^2. Find its acceleration when the velocity is zero.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2016Subjective· 2mImportance★★★★★
83% · 132/160 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Differentiate displacement to get velocity, find tt where v=0v=0, then differentiate velocity to get (constant) acceleration.

s=5+20t−2t2s=5+20t-2t^2

Velocity: v=dsdt=20−4tv=\dfrac{ds}{dt}=20-4t

Set v=0v=0: 20−4t=0⇒t=520-4t=0 \Rightarrow t=5

Acceleration: a=dvdt=−4a=\dfrac{dv}{dt}=-4

…

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.