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Question 283 of 293

Q.The slope of the tangent to the curve x=sin⁡θx=\sin\theta and y=cos⁡2θy=\cos 2\theta at θ=π6\theta = \dfrac{\pi}{6} is ____.

(a) −23-2\sqrt{3}
(b) −23\dfrac{-2}{\sqrt{3}}
(c) −2-2
(d) −12-\dfrac{1}{2}
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2024MCQ· 2mImportance★★★★★
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dydx=dy/dθdx/dθ=−4sin⁡θ\dfrac{dy}{dx}=\dfrac{dy/d\theta}{dx/d\theta}=-4\sin\theta.

x=sin⁡θ⇒dxdθ=cos⁡θx=\sin\theta \Rightarrow \dfrac{dx}{d\theta}=\cos\theta

y=cos⁡2θ⇒dydθ=−2sin⁡2θ=−4sin⁡θcos⁡θy=\cos2\theta \Rightarrow \dfrac{dy}{d\theta}=-2\sin2\theta=-4\sin\theta\cos\theta

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