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Question 233 of 255

Q.Evaluate: ∫dxx2+4x+8\displaystyle\int \dfrac{dx}{x^2+4x+8}

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2020Subjective· 2mImportance★★★★★
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Complete the square in the denominator, then use the standard ∫dxu2+a2\int \frac{dx}{u^2+a^2} form.

x2+4x+8=(x+2)2+4x^2+4x+8 = (x+2)^2+4

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