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Q.Evaluate: ∫125−9x2 dx\displaystyle\int \dfrac{1}{25-9x^2}\,dx

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2025Subjective· 2mImportance★★★★★
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Write 25−9x2=52−(3x)225-9x^2=5^2-(3x)^2 and use the standard formula ∫dua2−u2=12aln⁡∣a+ua−u∣+c\int\dfrac{du}{a^2-u^2}=\dfrac{1}{2a}\ln\left|\dfrac{a+u}{a-u}\right|+c.

∫125−9x2 dx=∫152−(3x)2 dx\int\frac{1}{25-9x^2}\,dx=\int\frac{1}{5^2-(3x)^2}\,dx

Let u=3xu=3x, du=3 dxdu=3\,dx: …

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