Q.Find the feasible solution of the following inequations graphically :
Draw the boundary line of each constraint () using its intercepts, shade the half-plane each inequation demands (test the origin, or another convenient point, in each), and darken the region common to all of them. The corner points of this common region are found by solving each pair of adjacent boundary lines simultaneously and keeping only the intersections that also satisfy every other constraint. Doing this here gives the vertices (2, 0), (3, 0), (0, 2), forming a triangle (bounded). Notice both boundary lines happen to pass through the same point , so the region is a triangle, not a quadrilateral.
Feasible region = the triangle (bounded) with vertices (2, 0), (3, 0), (0, 2) (all points satisfying every given inequation simultaneously).
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