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Exercise 7.2 · Q24

Q.Find the feasible solution of the following inequations graphically : 3x+4y≥12, 4x+7y≤28, y≥1, x≥03x + 4y \ge 12,\ 4x + 7y \le 28,\ y \ge 1,\ x \ge 0

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✓ Free question

Draw the boundary line of each constraint (3x+4y≥12, 4x+7y≤28, y≥1, x≥03x+4y\ge12,\ 4x+7y\le28,\ y\ge1,\ x\ge0) using its intercepts, shade the half-plane each inequation demands (test the origin, or another convenient point, in each), and darken the region common to all of them. The corner points of this common region are found by solving each pair of adjacent boundary lines simultaneously and keeping only the intersections that also satisfy every other constraint. Doing this here gives the vertices (0, 3), (0, 4), (\tfrac{21}{4}, 1), (\tfrac{8}{3}, 1), forming a quadrilateral (bounded).

✓Final answer

Feasible region = the quadrilateral (bounded) with vertices (0, 3), (0, 4), (\tfrac{21}{4}, 1), (\tfrac{8}{3}, 1) (all points satisfying every given inequation simultaneously).

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