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Exercise 7.2 · Q28

Q.A company produces two types of articles A and B which requires silver and gold. Each unit of A requires 3 gm of silver and 1 gm of gold, while each unit of B requires 2 gm of silver and 2 gm of gold. The company has 6 gm of silver and 4 gm of gold. Construct the inequations and find the feasible solution graphically.

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Let xx = number of units of article A and yy = number of units of article B produced. Each unit of A needs 3 gm silver and 1 gm gold; each unit of B needs 2 gm silver and 2 gm gold; only 6 gm silver and 4 gm gold are available. This gives the silver constraint 3x+2y≤63x+2y\le6 and the gold constraint x+2y≤4x+2y\le4, together with the non-negativity constraints x≥0,y≥0x\ge0,y\ge0 (a negative number of articles is meaningless). Drawing the lines 3x+2y=63x+2y=6 (through (2,0)(2,0) and (0,3)(0,3)) and x+2y=4x+2y=4 (through (4,0)(4,0) and (0,2)(0,2)) and shading the origin side of each (since (0,0)(0,0) satisfies both with slack), the common shaded region is …

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