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Physics · Ch 14 — Dual Nature of Radiation and Matter

De Broglie Hypothesis

14.5

De Broglie Hypothesis

In 1924, Prince Louis de Broglie made a striking proposal based purely on an argument from symmetry in nature. If radiation -- normally thought of as a wave -- had been shown (through the photoelectric effect and Compton scattering) to also possess particle-like properties, then perhaps MATTER -- normally thought of as made of particles -- might, symmetrically, also possess wave-like properties. This was a bold guess with no direct experimental support at the time it was proposed; the confirming evidence (the Davisson-Germer experiment) came a few years later and is described in the next section.

De Broglie built his hypothesis by directly extending the photon relations. For a photon, momentum and energy are related by p=E/cp=E/c (valid for any massless particle travelling at speed c, from Einstein's special relativity); combined with the Einstein relation E=hνE=h\nu and c=νλc=\nu\lambda, this gives

p=Ec=hνc=hλ— (14.5)p = \frac{E}{c} = \frac{h\nu}{c} = \frac{h}{\lambda} \qquad \text{--- (14.5)}

De Broglie proposed that this SAME relation should connect the wave properties (frequency ν\nu, wavelength λ\lambda) and particle properties (energy E, momentum p) of ANY moving material particle, not just a photon. For a particle of mass m moving with velocity v (so p=mvp=mv), the associated MATTER WAVE has

ν=Ehandλ=hp=hmv— (14.6)\nu = \frac{E}{h} \qquad\text{and}\qquad \lambda = \frac{h}{p} = \frac{h}{mv} \qquad \text{--- (14.6)}

The wavelength given by Eq. (14.6) is called the DE BROGLIE WAVELENGTH, and Eq. (14.6) itself the DE BROGLIE RELATION. It immediately shows an inverse relationship between momentum and wavelength: the LARGER a particle's momentum, the SHORTER its de Broglie wavelength.

For a particle of mass m and kinetic energy EK=12mv2E_K=\frac{1}{2}mv^2 (so v=2EK/mv=\sqrt{2E_K/m}), substituting into λ=h/(mv)\lambda=h/(mv) gives the useful energy form

λ=hmv=h2mEK\lambda = \frac{h}{mv} = \frac{h}{\sqrt{2mE_K}}

For a CHARGED particle of charge q, accelerated from rest through a potential difference V, the work done qVqV equals the kinetic energy gained, so EK=qVE_K=qV, giving

λ=h2mqV\lambda = \frac{h}{\sqrt{2mqV}}

This relation applies to any charged particle -- electron, proton, or a charged ion -- with m being that particle's own mass; it stops being valid once V becomes so large that the particle's speed approaches the speed of light, where relativistic corrections (not covered in this course) become necessary. …

Misc Ex.14.4de Broglie wavelength of an electron accelerated through 120 V

Worked out. Applying the accelerated-electron formula λ(nm)=1.228/V\lambda(\text{nm})=1.228/\sqrt{V} derived in this section to an electron accelerated through a potential difference V = 120 V gives λ=1.228/120≈0.112\lambda=1.228/\sqrt{120}\approx0.112 nm -- a wavelength comparable to the spacing between atoms in a crystal lattice (a few tenths of a nanometre), which is exactly the length scale needed for the electron's matter wave to show observable diffraction effects when scattered from a crystal, foreshadowing the Davisson-Germer experiment described in th …