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Long Answer Questions · Q14

Q.Determine the series limit of Balmer, Paschen and Brackett series, given the limit for Lyman series is 911.6 Å.

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The series-limit wavelength for series n is λlimit=n2R\lambda_{limit}=\frac{n^2}{R} (setting m→∞m\rightarrow\infty in 1/λ=R(1/n2−1/m2)1/\lambda=R(1/n^2-1/m^2)). Since the Lyman limit (n=1) is given as λL=1/R=911.6\lambda_{L}=1/R=911.6 Å, the value 1/R1/R itself is fixed at 911.6 Å, so every other series' limit is simply n2×911.6n^2\times911.6 Å. For Balmer (n=2): λB=4×911.6=3646.4\lambda_B=4\times911.6=3646.4 Å ≈3646\approx3646 Å. For Paschen (n=3): …

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