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NCERT Exemplar · Q72

Q.Assertion: Ethanol is a weaker acid than phenol.
Reason: Sodium ethoxide may be prepared by the reaction of ethanol with aqueous NaOH.

(i) Assertion and reason both are correct statements and reason is the correct explanation for assertion.
(ii) Assertion and reason both are correct statements but reason is not the correct explanation for assertion.
(iii) Assertion is correct statement but reason is wrong statement.
(iv) Assertion is wrong statement but reason is correct statement.
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The assertion -- ethanol is a weaker acid than phenol -- is correct, because the phenoxide ion is resonance-stabilised while the ethoxide ion is not. But the reason -- that sodium ethoxide can be prepared by reacting ethanol with aqueous NaOH -- is factually wrong: aqueous NaOH cannot effectively deprotonate ethanol, because water is itself a slightly stronger acid than ethanol. The correct option is (iii).

Why This Question Tests Conceptual Depth

This assertion-reason question checks two separate things: whether you know ethanol is a weaker acid than phenol, and whether you know how sodium ethoxide is actually prepared.

1. The assertion: ethanol vs. phenol acidity

Acidity depends on the stability of the conjugate base after losing H+.

  • Phenol (C6H5OHC_6H_5OH) loses H+ to form the phenoxide ion (C6H5O−C_6H_5O^-), whose negative charge is delocalised into the aromatic ring by resonance. This stabilisation makes phenol give up its proton comparatively easily.
  • Ethanol (CH3CH2OHCH_3CH_2OH) loses H+ to form the ethoxide ion (CH3CH2O−CH_3CH_2O^-), where the charge stays localised on oxygen -- no resonance is possible.

Relative acidity: Phenol (pKa ~10) is stronger than Ethanol (pKa ~16). The assertion is correct.

2. The reason: can sodium ethoxide be made from ethanol + aqueous NaOH?

This part is wrong. Consider the equilibrium:

CH3CH2OH + NaOH <=> CH3CH2ONa + H2O

For this to proceed usefully to the right, hydroxide would have to be a better base than ethoxide -- i.e. water would have to be a weaker acid than ethanol. The opposite is true: water's pKa (~15.7) is slightly lower than ethanol's (~16), meaning water is the marginally stronger acid and hydroxide the weaker base. So the equilibrium lies almost entirely on the reactant side -- aqueous NaOH does not give a useful yield of sodium ethoxide. …

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