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Exercise 2 · Q1

Q.Find φ(35)\varphi(35).

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✓ Free question

As 35=5×735 = 5\times 7 (both prime), Euler's totient gives φ(35)=35(1−15)(1−17)=24\varphi(35) = 35\left(1-\tfrac15\right)\left(1-\tfrac17\right) = 24.

φ(n)=n∏p∣n(1−1p)\varphi(n) = n\prod_{p\mid n}\left(1 - \frac{1}{p}\right)

where the product runs over the distinct prime factors pp of nn. Here n=35n = 35.

  1. Factorise. 35=5×735 = 5 \times 7; distinct primes are 55 and 77.
  2. Apply the formula: φ(35)=35(1−15)(1−17)=35×45×67\varphi(35) = 35\left(1 - \dfrac15\right)\left(1 - \dfrac17\right) = 35 \times \dfrac{4}{5} \times \dfrac{6}{7}.
  3. Simplify. 35×45=2835 \times \dfrac45 = 28, then 28×67=2428 \times \dfrac67 = 24.
  4. Check (multiplicativity): for coprime primes, φ(5)=4\varphi(5) = 4 and φ(7)=6\varphi(7) = 6, so φ(35)=4×6=24\varphi(35) = 4\times 6 = 24. ✓
✓Final answer

φ(35)=24\varphi(35) = 24.

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