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Worked Examples · Example 16

Q.Find τ(12)\tau(12).

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τ(12)\tau(12) counts the divisors of 1212; from 12=22×312 = 2^2\times 3 the count is (2+1)(1+1)=6(2+1)(1+1) = 6.

τ(n)=∏i(ai+1)for n=∏ipiai\tau(n) = \prod_i (a_i + 1)\quad\text{for }n = \prod_i p_i^{a_i}

where τ(n)\tau(n) is the number of positive divisors and aia_i are the exponents in the prime factorisation.

  1. Factorise n=12n = 12:

12=22×3112 = 2^2\times 3^1

exponents are a1=2a_1 = 2 and a2=1a_2 = 1. …

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