Skip to content
Worked Examples · Example 18

Q.Find μ(12)\mu(12) and μ(35)\mu(35).

Puducherry CbseNCERTSubjective· 2mImportance★★★★★est
17% · 18/106 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Factorise each number. 12=22⋅312=2^2\cdot 3 is not square-free, so μ(12)=0\mu(12)=0; 35=5⋅735=5\cdot 7 is square-free with 22 prime factors, so μ(35)=(−1)2=1\mu(35)=(-1)^2=1.

The Möbius function μ(n)\mu(n) is defined as:

μ(n)={1n=1(−1)kn=p1p2⋯pk (distinct primes, square-free)0n has a squared prime factor\mu(n)=\begin{cases}1 & n=1\\ (-1)^k & n=p_1p_2\cdots p_k\ (\text{distinct primes, square-free})\\ 0 & n\text{ has a squared prime factor}\end{cases}

where kk is the number of distinct prime factors.

  1. Factorise 1212: 12=2×2×3=22⋅312=2\times 2\times 3=2^2\cdot 3. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.