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Exercise 1 · Q3

Q.Find the value of xx, given that x≡23(mod7)x \equiv 23 \pmod 7; if 21≤x<3121 \le x < 31.

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✓ Free question

The congruence x≡23≡2(mod7)x\equiv 23\equiv 2\pmod 7 is satisfied by x=23x=23 and x=30x=30 inside the range 21≤x<3121\le x<31.

x≡23(mod7) ⟺ x=23+7k, k∈Zx \equiv 23 \pmod 7 \ \Longleftrightarrow\ x = 23 + 7k,\ k\in\mathbb{Z}

subject to 21≤x<3121 \le x < 31.

  1. Reduce the residue. 23=3×7+2⇒23≡2(mod7)23 = 3\times 7 + 2 \Rightarrow 23 \equiv 2 \pmod 7, so x≡2(mod7)x\equiv 2\pmod 7.
  2. List candidates in [21,31)[21, 31) and take their remainders mod 77:
xxx mod 7x \bmod 7
210
221
232
243
254
265
276
280
291
302
  1. Select those ≡2\equiv 2. x=23x = 23 and x=30x = 30 satisfy x≡2(mod7)x\equiv 2\pmod 7 within 21≤x<3121 \le x < 31.
✓Final answer

x=23x = 23 and x=30x = 30.

Note

The book's printed answer key (Exercise-1, Q3) lists only x=30x = 30 and omits x=23x = 23. However 23≡2(mod7)23 \equiv 2 \pmod 7 and 21≤23<3121 \le 23 < 31, so x=23x = 23 is an equally valid solution; the complete answer therefore includes both 2323 and 3030.

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