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Exercise 1 · Q5

Q.Evaluate (16×29)(mod7)(16 \times 29) \pmod 7.

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Reduce each factor mod 77 first (16→216\to2, 29→129\to1); the product 2×1=22\times1=2 gives the answer 2.

(a×b) mod m=((a mod m)×(b mod m)) mod m(a\times b)\bmod m = \big((a\bmod m)\times(b\bmod m)\big)\bmod m

Here a=16, b=29, m=7a=16,\ b=29,\ m=7.

  1. Reduce each factor: 16=2×7+2⇒16≡2(mod7)16 = 2\times7 + 2 \Rightarrow 16\equiv 2\pmod 7; 29=4×7+1⇒29≡1(mod7)29 = 4\times7 + 1 \Rightarrow 29\equiv 1\pmod 7. …

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