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Worked Examples · Example 7

Q.(i) Find subtraction modulo 8 if aa and bb are 11 and 3 respectively.

(ii) Apply subtraction modulo to positive integers 15 and 6 for modulo 25.
(iii) Find a−mba -_m b, if a=17a = 17, b=13b = 13 and m=3m = 3.
(iv) Find a−mba -_m b, if a=11a = 11, b=43b = 43 and m=7m = 7.
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Subtraction modulo mm is a⊖mb=(a−b) mod ma\ominus_m b = (a-b)\bmod m, always reduced to a value in {0,1,…,m−1}\{0,1,\dots,m-1\}; the four results are 0, 9, 1, 30,\ 9,\ 1,\ 3.

a⊖mb=(a−b) mod ma\ominus_m b = (a-b)\bmod m

where a,ba,b are the operands and mm is the modulus. If a−ba-b is negative, add multiples of mm until the result lies in {0,…,m−1}\{0,\dots,m-1\}.

  1. (i) a=11, b=3, m=8a=11,\ b=3,\ m=8:

11−3=8,8 mod 8=011-3 = 8,\qquad 8\bmod 8 = 0

So 11⊖83=011\ominus_8 3 = 0.

  1. (ii) a=15, b=6, m=25a=15,\ b=6,\ m=25:

15−6=9,9 mod 25=915-6 = 9,\qquad 9\bmod 25 = 9

So 15⊖256=915\ominus_{25} 6 = 9.

  1. (iii) a=17, b=13, m=3a=17,\ b=13,\ m=3:

17−13=4,4 mod 3=117-13 = 4,\qquad 4\bmod 3 = 1

since 4=1×3+14 = 1\times 3 + 1. So 17⊖313=117\ominus_3 13 = 1. …

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