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Question 34 of 47

Q.Find the focus and vertex of the parabola y2=20xy^2 = 20x.

Puducherry TnboardTamil Nadu HSC First Year (DGE) Commerce Board 2023Subjective· 2mImportance★★★★★
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For y2=20xy^2 = 20x, 4a=20⇒a=54a = 20 \Rightarrow a = 5; vertex (0,0)(0,0), focus (5,0)(5,0).

The standard right-opening parabola with vertex at the origin is

y2=4ax,y^2 = 4ax,

with vertex (0,0)(0, 0) and focus (a,0)(a, 0).

Compare with y2=20xy^2 = 20x:

4a=20  ⇒  a=5.4a = 20 \;\Rightarrow\; a = 5.

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