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Question 36 of 47

Q.If m1m_1 and m2m_2 are the slopes of the pair of lines given by ax2+2hxy+by2=0ax^2+2hxy+by^2=0, then the value of m1+m2m_1+m_2 is :

(a) 2ha\dfrac{2h}{a}
(b) 2hb\dfrac{2h}{b}
(c) −2ha-\dfrac{2h}{a}
(d) −2hb-\dfrac{2h}{b}
Puducherry TnboardTamil Nadu HSC First Year (DGE) Commerce Board 2024MCQ· 1mImportance★★★★★
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For ax2+2hxy+by2=0ax^2+2hxy+by^2=0, the sum of the slopes is m1+m2=−2hbm_1+m_2=-\dfrac{2h}{b}.

Dividing the equation ax2+2hxy+by2=0ax^2+2hxy+by^2=0 by x2x^2 and writing m=yxm=\dfrac{y}{x} (the slope of each line through the origin) gives the quadratic in mm:

bm2+2hm+a=0.bm^2+2hm+a=0.

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