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Question 37 of 47

Q.Find the equation of the circle with centre at (4,5)(4,5) and radius 3 units.

(a) x2+y2−8x−10y+32=0x^2+y^2-8x-10y+32=0
(b) x2+y2−6x+2y−6=0x^2+y^2-6x+2y-6=0
(c) x2+y2−8x−6y=0x^2+y^2-8x-6y=0
(d) x2+y2+8x−10y=0x^2+y^2+8x-10y=0
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The circle with centre (4,5)(4,5) and radius 33 is x2+y2−8x−10y+32=0x^2+y^2-8x-10y+32=0.

The standard form of a circle with centre (h,k)(h,k) and radius rr is:

(x−h)2+(y−k)2=r2.(x-h)^2+(y-k)^2=r^2.

Substitute h=4, k=5, r=3h=4,\ k=5,\ r=3:

(x−4)2+(y−5)2=32=9.(x-4)^2+(y-5)^2=3^2=9.

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