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Q.Find the co-ordinates of the focus, vertex, equation of the directrix of the parabola x2=8yx^2=8y

Puducherry TnboardTamil Nadu HSC First Year (DGE) Commerce Board 2025Subjective· 3mImportance★★★★★
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x2=8y⇒4a=8⇒a=2x^2=8y\Rightarrow 4a=8\Rightarrow a=2; upward parabola: vertex (0,0)(0,0), focus (0,a)=(0,2)(0,a)=(0,2), directrix y=−a=−2y=-a=-2.

Given: parabola x2=8yx^2=8y.

Step 1 — compare with the standard form x2=4ayx^2=4ay.

4a=8  ⇒  a=2.4a=8\;\Rightarrow\;a=2.

Since the form is x2=4ayx^2=4ay with a>0a>0, the parabola opens upward with vertex at the origin.

Step 2 — write down the elements.

  • Vertex: (0,0)(0,0). …

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