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Choose the Best Answer · Q15

Q.Bond order of a species is 2.5 and the number of electrons in its bonding molecular orbital is found to be 8. The number of electrons in its antibonding molecular orbital is

(a) three
(b) four
(c) Zero
(d) cannot be calculated from the given information.
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Step 1. BO=Nb−Na2BO = \dfrac{N_b - N_a}{2}, with BO=2.5BO = 2.5 and Nb=8N_b = 8 given.

Step 2. 2.5=8−Na22.5 = \dfrac{8 - N_a}{2} …

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