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Write Brief Answer · Q5

Q.Draw the M.O diagram for oxygen molecule, calculate its bond order and show that O₂ is paramagnetic.

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Step 1. Oxygen's atomic configuration is 1s² 2s² 2p⁴ (each O atom contributes these orbitals to the molecule).

Step 2. Building up O₂'s molecular orbitals by the Aufbau/Pauli/Hund rules (with σ2px sitting below the degenerate π2p pair for this diatomic) gives: σ1s² σ1s² σ2s² σ2s² σ2px² π2py² π2pz² π2py¹ π2pz¹ — 16 electrons total, matching 2 × 8.

Step 3. Bond order. NbN_b (bonding electrons) = σ1s(2) + σ2s(2) + σ2px(2) + π2py(2) + π2pz(2) = 10. NaN_a (antibonding electrons) = σ1s(2) + σ2s(2) + π2py(1) + π2pz(1) = 6. BO=(10−6)/2=2BO = (10-6)/2 = 2 — consistent with the O=O double bond of the Lewis picture.

Step 4. Diagram. The MO diagram shows σ1s, σ1s, σ2s, σ2s, σ2px, π2py, π2pz all fully filled (paired), with the degenerate π2py and π2pz orbitals each holding just ONE electron (per Hund's rule, they fill singly before pairing). …

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