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Write Brief Answer · Q23

Q.Which one of the following has highest bond order?
N₂, N₂⁺ or N₂⁻

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Step 1. N₂ (14 electrons): MO configuration σ1s²σ1s²σ2s²σ2s²π2py²π2pz²σ2px². Nb=10N_b=10, Na=4N_a=4, BO=(10−4)/2=3BO=(10-4)/2=3.

Step 2. N₂⁺ (13 electrons, one electron removed from N₂'s highest-energy filled orbital, σ2px): configuration ...π2py²π2pz²σ2px¹. Nb=9N_b=9, Na=4N_a=4, BO=(9−4)/2=2.5BO=(9-4)/2=2.5.

Step 3. N₂⁻ (15 electrons, one electron added to the next available orbital, the antibonding π2p level): configuration ...σ2px²π2py¹. Nb=10N_b=10, Na=5N_a=5, BO=(10−5)/2=2.5BO=(10-5)/2=2.5. …

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