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Q.Calculate the molality of the solution containing 90 g of glucose dissolved in 2 kg of water.

Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2024Subjective· 2mImportance★★★★★
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90 g of glucose is 0.5 mol; dividing by 2 kg of water gives a molality of 0.25 mol/kg.

Step 1 — Molar mass of glucose (C6H12O6): 6(12) + 12(1) + 6(16) = 72 + 12 + 96 = 180 g/mol.

Step 2 — Moles of glucose (solute): moles = mass / molar mass = 90 g / 180 g/mol = 0.5 mol.

Step 3 — Mass of solvent (water) in kg: given directly as 2 kg.

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