Question 64 of 67
Q.The Van't Hoff Factor
(i) for a dilute aqueous solution of the strong electrolyte barium hydroxide is :
(a) 2
(b) 0
(c) 3
(d) 1
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Start your 14-day free trial to unlock the full solution →Ba(OH)2 is a strong electrolyte that dissociates completely into 3 ions per formula unit in dilute aqueous solution, so its van't Hoff factor i = 3.
The van't Hoff factor i is defined as the ratio of the actual number of particles produced in solution to the number of formula units dissolved:
i = (moles of particles in solution after dissociation) / (moles of solute dissolved)
Barium hydroxide dissociates in water as:
Ba(OH)2(aq) -> Ba2+(aq) + 2OH-(aq)
…
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