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Exercise 11.5 · Q3

Q.(2x−5)(36+4x)(2x-5)(36+4x)

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This is a straightforward polynomial once the two linear factors are multiplied out.

Step 1. Expand. (2x−5)(36+4x)=72x+8x2−180−20x=8x2+52x−180(2x-5)(36+4x)=72x+8x^2-180-20x=8x^2+52x-180.

Step 2. Integrate term by term. ∫8x2dx=8x33\displaystyle\int 8x^2dx=\dfrac{8x^3}3, ∫52x dx=26x2\displaystyle\int 52x\,dx=26x^2, ∫(−180)dx=−180x\displaystyle\int(-180)dx=-180x.

Step 3. Combine. ∫(2x−5)(36+4x) dx=8x33+26x2−180x+c\displaystyle\int(2x-5)(36+4x)\,dx=\dfrac{8x^3}3+26x^2-180x+c.

Step 4. Check. Differentiating: 8x2+52x−1808x^2+52x-180, matching Step 1.

✓Final answer

8x33+26x2−180x+c\dfrac{8x^3}{3}+26x^2-180x+c

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