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Exercise 11.5 · Q9

Q.sin⁡4xsin⁡x\dfrac{\sin 4x}{\sin x}

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Repeated double-angle expansion of sin⁡4x\sin4x produces a factor of sin⁡x\sin x that cancels with the denominator, leaving a decomposable trig product.

Step 1. Expand via double angle twice. sin⁡4x=2sin⁡2xcos⁡2x=2(2sin⁡xcos⁡x)(1−2sin⁡2x)=4sin⁡xcos⁡x−8sin⁡3xcos⁡x\sin4x=2\sin2x\cos2x=2(2\sin x\cos x)(1-2\sin^2x)=4\sin x\cos x-8\sin^3x\cos x.

Step 2. Divide by sin⁡x\sin x. sin⁡4xsin⁡x=4cos⁡x−8sin⁡2xcos⁡x\dfrac{\sin4x}{\sin x}=4\cos x-8\sin^2x\cos x. …

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