Skip to content
Exercise 11.5 · Q7

Q.3+4cos⁡xsin⁡2x\dfrac{3+4\cos x}{\sin^2 x}

Puducherry TnboardTextbookSubjectiveImportance★★★★★
21% · 27/129 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Dividing both terms of the numerator by sin⁡2x\sin^2x produces two directly recognisable derivative forms.

Step 1. Split the fraction. 3+4cos⁡xsin⁡2x=3sin⁡2x+4cos⁡xsin⁡2x=3csc⁡2x+4csc⁡xcot⁡x\dfrac{3+4\cos x}{\sin^2x}=\dfrac3{\sin^2x}+\dfrac{4\cos x}{\sin^2x}=3\csc^2x+4\csc x\cot x (using cos⁡xsin⁡2x=1sin⁡x⋅cos⁡xsin⁡x=csc⁡xcot⁡x\dfrac{\cos x}{\sin^2x}=\dfrac1{\sin x}\cdot\dfrac{\cos x}{\sin x}=\csc x\cot x).

Step 2. Integrate each piece. ∫3csc⁡2x dx=−3cot⁡x\displaystyle\int3\csc^2x\,dx=-3\cot x, ∫4csc⁡xcot⁡x dx=−4csc⁡x\displaystyle\int4\csc x\cot x\,dx=-4\csc x. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.