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Question 80 of 104

Q.Construct a suitable domain X such that f:X→Nf: X\to N defined by f(n)=n+3f(n)=n+3 to be one to one and onto.

Puducherry TnboardTamil Nadu HSC First Year (DGE) Board 2019Subjective· 3mImportance★★★★★
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Shifting the domain so that n+3n+3 ranges over exactly {1,2,3,…}\{1,2,3,\ldots\} requires nn to range over {−2,−1,0,1,2,…}\{-2,-1,0,1,2,\ldots\}, which makes ff both one-one and onto.

For f(n)=n+3f(n)=n+3 to be onto N={1,2,3,…}N=\{1,2,3,\ldots\}, every natural number kk must be hit: n+3=k⇒n=k−3n+3=k \Rightarrow n=k-3. As kk ranges over 1,2,3,…1,2,3,\ldots, n=k−3n=k-3 ranges over −2,−1,0,1,2,…-2,-1,0,1,2,\ldots.

So take X={−2,−1,0,1,2,3,…}={n∈Z:n≥−2}X = \{-2,-1,0,1,2,3,\ldots\} = \{n\in\mathbb{Z}: n\ge-2\}.

Onto: every k∈Nk\in N has a preimage n=k−3∈Xn=k-3\in X, as shown above.

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